3(x+2)=5[x-(3-x)]

Solution for 3(x+2)=5[x-(3-x)] equation:

Simplifying
3(x + 2) = 5[x + -1(3 + -1x)]

Reorder the terms:
3(2 + x) = 5[x + -1(3 + -1x)]
(2 * 3 + x * 3) = 5[x + -1(3 + -1x)]
(6 + 3x) = 5[x + -1(3 + -1x)]
6 + 3x = 5[x + (3 * -1 + -1x * -1)]
6 + 3x = 5[x + (-3 + 1x)]

Reorder the terms:
6 + 3x = 5[-3 + x + 1x]

Combine like terms: x + 1x = 2x
6 + 3x = 5[-3 + 2x]
6 + 3x = [-3 * 5 + 2x * 5]
6 + 3x = [-15 + 10x]

Solving
6 + 3x = -15 + 10x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-10x' to each side of the equation.
6 + 3x + -10x = -15 + 10x + -10x

Combine like terms: 3x + -10x = -7x
6 + -7x = -15 + 10x + -10x

Combine like terms: 10x + -10x = 0
6 + -7x = -15 + 0
6 + -7x = -15

Add '-6' to each side of the equation.
6 + -6 + -7x = -15 + -6

Combine like terms: 6 + -6 = 0
0 + -7x = -15 + -6
-7x = -15 + -6

Combine like terms: -15 + -6 = -21
-7x = -21

Divide each side by '-7'.
x = 3

Simplifying
x = 3